The equation of lines that through (4,1) and (6,-2) is...
Jawaban
from the first point:
x1=4, y1=1
from the second point:
x2=6, y2=-2
the calculation:
| y2-y | = | y2-y1 |
| x2-x | x2-x1 | |
| -2-y | = | -2-1 |
| 6-x | 6-4 | |
| -2-y | = | -3 |
| 6-x | 2 | |
| 2(-2-y) | = | -3(6-x) |
| -4-2y | = | -18+3x |
| -3x-2y+14 | = | 0 |
| or | ||
| 3x+2y-14 | = | 0 |
